-3(x^2-2)+2(3-2x^2)=

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Solution for -3(x^2-2)+2(3-2x^2)= equation:


Simplifying
-3(x2 + -2) + 2(3 + -2x2) = 0

Reorder the terms:
-3(-2 + x2) + 2(3 + -2x2) = 0
(-2 * -3 + x2 * -3) + 2(3 + -2x2) = 0
(6 + -3x2) + 2(3 + -2x2) = 0
6 + -3x2 + (3 * 2 + -2x2 * 2) = 0
6 + -3x2 + (6 + -4x2) = 0

Reorder the terms:
6 + 6 + -3x2 + -4x2 = 0

Combine like terms: 6 + 6 = 12
12 + -3x2 + -4x2 = 0

Combine like terms: -3x2 + -4x2 = -7x2
12 + -7x2 = 0

Solving
12 + -7x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -7x2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -7x2 = 0 + -12
-7x2 = 0 + -12

Combine like terms: 0 + -12 = -12
-7x2 = -12

Divide each side by '-7'.
x2 = 1.714285714

Simplifying
x2 = 1.714285714

Take the square root of each side:
x = {-1.309307341, 1.309307341}

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